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-36=-81p^2
We move all terms to the left:
-36-(-81p^2)=0
We get rid of parentheses
81p^2-36=0
a = 81; b = 0; c = -36;
Δ = b2-4ac
Δ = 02-4·81·(-36)
Δ = 11664
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{11664}=108$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-108}{2*81}=\frac{-108}{162} =-2/3 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+108}{2*81}=\frac{108}{162} =2/3 $
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